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Error: convert: missing an image filename 'filename.gif'

Posted: 2008-12-12T23:06:05-07:00
by sabater_wb
I'm tying to do something like this code

convert rose: -compose Screen \
\( -clone 0 stars1.gif -composite \) \
\( -clone 0 stars2.gif -composite \) \
\( -clone 0 stars3.gif -composite \) \
-delete 0 -set delay 25 -layers Optimize rose_sparkle.gif


I typed on windows prompt

Code: Select all

convert rose -compose Screen -clone 0 image001.gif -composite -clone 0 image002.gif -composite -delete 0 -set delay 25 -layers Optimize result.gif
And I got an error: "convert: missing an image filename 'result.gif'.

So, I'm thinking. How is it possible if result.gif is the output file name?

What is wrong?

Re: Error: convert: missing an image filename 'filename.gif'

Posted: 2008-12-13T08:18:32-07:00
by el_supremo
Same problem as your other post. You've left out the parentheses. And you also need a colon after "rose" - it must be rose:

Pete

Re: Error: convert: missing an image filename 'filename.gif'

Posted: 2011-07-09T05:15:57-07:00
by kbirecki
I know this is an old thread, but for future readers, another cause can be incorrect registry entries pointing to GhostScript. There is a simple solution that I found and I made it my first blog entry: http://hallsoftech.blogspot.com/2011/07 ... image.html.